Point charge attractioning a positive charge from infinity to 30cm

AI Thread Summary
To calculate the work required to bring a positive charge of 4.0 x 10^-9 C from infinity to 30 cm from a point charge of 2.0 x 10^-9 C, the formula W = -q2(ΔV) is used, where ΔV = Ke * q1/d. The user initially misapplied the charge values, switching q1 and q2 without realizing it does not affect the outcome. The final expression for work must be shown clearly, including the values substituted, and the sign of the result should be noted. The discussion emphasizes the importance of correctly applying the formula and understanding the signs in electrostatics.
goWlfpack
Messages
51
Reaction score
0

Homework Statement



A point charge of 2.0 10-9 C is located at the origin. How much work is required to bring a positive charge of 4.0 10-9 C from infinity to the location x = 30.0 cm?

and it requests the answer in J

Homework Equations



W=-q2(delta)V

DeltaV = Ke q1/d

where delta v is potential difference, W is work, q2 and q1 are the charges, Ke is coulombs constant, and d is distance



The Attempt at a Solution



I plugged in all of the variables using 4.0 *10 ^ -9 as my q1 and 2.0*10^-9 as my q2 and that was wrong so i switched them.. again wrong..
 
Physics news on Phys.org
Switching q1 and q2 won't change anything. Show your final expression for the work done and the numbers you plugged in. Is it positive or negative?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top