Point charge ; current in a circuit

Click For Summary

Discussion Overview

The discussion revolves around the behavior of an LC parallel tank circuit when a switch is introduced in the middle of the inductor. Participants explore the implications of closing the switch on current and voltage at the moment of closure, as well as the relationship between electric potential and charge. The conversation includes theoretical considerations and interpretations of electric potential in relation to charged particles.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants question whether any current or voltage would be felt at the switch immediately after it is closed, given the presence of an inductor which opposes changes in current.
  • It is suggested that the full voltage drop of the circuit is initially across the open switch, and that after closing the switch, the voltage drop will be divided among circuit components.
  • Some participants propose that very little to no current flows through the switch at the first instant due to the inductor's back EMF, which opposes the current buildup.
  • There is discussion about the electric potential being independent of the charge value, leading to questions about whether a single electron at high potential has the same field strength as multiple electrons at the same potential.
  • One participant mentions that the electric potential can be calculated at a point in either static or dynamic electric fields, emphasizing that it is a property of the electric field itself.
  • Another participant expresses confusion about how to interpret electric potential when considering a very high potential over a small area with minimal charge.

Areas of Agreement / Disagreement

Participants express varying interpretations regarding the behavior of current and voltage at the switch upon closure, with no consensus reached on the specifics of the first instant after the switch is closed. Additionally, there is ongoing confusion and debate about the implications of electric potential in relation to charge.

Contextual Notes

Participants highlight the importance of the rate of change of the magnetic field in relation to back EMF, indicating that the strength of the magnetic field itself may not be the primary factor affecting current flow. The discussion also reflects uncertainty regarding the definitions and implications of electric potential in different contexts.

Crazymechanic
Messages
831
Reaction score
12
Hello , there are two questions I would like to ask from a educational paper i just read.

For the first question please look the attached picture , it says that in the picture of the capacitor with the wire that has a gap in the middle and next to it when the gap is closed , it says that in the exact middle of that wire between the two plates the wire is neutral , that would imply no charge , well first of all even if that happens , for how long as i basically see a charged capacitor being short circuited with a wire which would basically discharge the cap.

Let me rephrase the question , imagine a LC parallel tank circuit , only in the middle of the inductor cut the wire in half and place a switch in series , now charge the capacitor while the switch is open , once the capacitor is charged , close the switch , the question is for the first instant would the switch being in the middle feel any current/voltage through it ? as the current would form when the switch is closed but because going through an inductor it would build up a magnetic field which would oppose the current so at the first instant the inductor would act as a " choke" , so what happens with the switch in the middle ?

there has been some discussion about this here on PF but I still haven't got a clear answer so I'm going to ask this one more time.
The paper i read says that the electric potential is independent of the value of q ,(q being the fundamental charge strength of a charged particle)
So does that mean that I can have one electron at say million volts of potential which has the same field strength around it as say 10 electrons at the same potential or no?
 

Attachments

  • Untitled.png
    Untitled.png
    58.2 KB · Views: 534
Physics news on Phys.org
Crazymechanic said:
Let me rephrase the question , imagine a LC parallel tank circuit , only in the middle of the inductor cut the wire in half and place a switch in series , now charge the capacitor while the switch is open , once the capacitor is charged , close the switch , the question is for the first instant would the switch being in the middle feel any current/voltage through it ?

The full voltage drop of the circuit is felt across the open switch initially. After closing the switch current will flow and the voltage drop will be divided appropriately between all components in the circuit. I don't know about "the first instant".

as the current would form when the switch is closed but because going through an inductor it would build up a magnetic field which would oppose the current so at the first instant the inductor would act as a " choke" , so what happens with the switch in the middle ?

If we assume the switch has identical resistance and is the same dimensions as the length of wire it replaced, then the inductor acts the same in both cases.

The paper i read says that the electric potential is independent of the value of q ,(q being the fundamental charge strength of a charged particle)
So does that mean that I can have one electron at say million volts of potential which has the same field strength around it as say 10 electrons at the same potential or no?

I'm not sure. Wiki says the following about electric potential:

The electric potential at a point is equal to the electric potential energy (measured in joules) of any charged particle at that location divided by the charge (measured in coulombs) of the particle. Since the charge of the test particle has been divided out, the electric potential is a "property" related only to the electric field itself and not the test particle. The electric potential can be calculated at a point in either a static (time-invariant) electric field or in a dynamic (varying with time) electric field at a specific time, and has the units of joules per coulomb (J C–1), or volts (V).
 
Well I guess very little to no current flows through the switch in the first instant (by instant I mean the time it takes for a certain inductor , voltage and current to produce an magnetic field in the coil)

So after you close the switch there should be a small time period at which all or most of the inrushing current is blocked due to the back emf of the coil right? After the field decreases the current starts to run but what happens at the moment and shortly before the moment of saturation that I guess is the question? As to my mind the current should be busy building up the field.


Still confused about the charged particle thing , well it says that " The electric potential at a point is equal to the electric potential energy (measured in joules) of any charged particle at that location divided by the charge (measured in coulombs) of the particle." As long as this goes it kinda makes me think that the potential is the overall potential divided by the particle potential , but that doesn't sound right.
But what if I have a gazillion volt potential over some physical are "x" and this area happens to be only one electron? What can I divide then?
 
Crazymechanic said:
Let me rephrase the question , imagine a LC parallel tank circuit , only in the middle of the inductor cut the wire in half and place a switch in series , now charge the capacitor while the switch is open , once the capacitor is charged , close the switch , the question is for the first instant would the switch being in the middle feel any current/voltage through it ?
The solution to a LC circuit is given here:
http://en.wikipedia.org/wiki/LC_circuit#Solution
http://farside.ph.utexas.edu/teaching/315/Waveshtml/node5.html

You start out with a voltage across the capacitor and no current. The current increases and the voltage decreases and they oscillate in a sinusoidal pattern.

Crazymechanic said:
The paper i read says that the electric potential is independent of the value of q ,(q being the fundamental charge strength of a charged particle)
So does that mean that I can have one electron at say million volts of potential which has the same field strength around it as say 10 electrons at the same potential or no?
That means that the electric potential does not depend on whether the charge on an electron is 1.6E-19 C or 2.8E-19C or 1.1E-19 C or whatever. All that changes is how many electrons are required to get the same charge.
 
Crazymechanic said:
Well I guess very little to no current flows through the switch in the first instant (by instant I mean the time it takes for a certain inductor , voltage and current to produce an magnetic field in the coil)

So after you close the switch there should be a small time period at which all or most of the inrushing current is blocked due to the back emf of the coil right? After the field decreases the current starts to run but what happens at the moment and shortly before the moment of saturation that I guess is the question? As to my mind the current should be busy building up the field.

The strength of the magnetic field is irrelevant. It is the rate of change in the field that causes back EMF. That's why, initially, the current is almost totally blocked. The rate of change is very very high even though the field is very small.
 

Similar threads

Replies
152
Views
8K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 61 ·
3
Replies
61
Views
6K
  • · Replies 36 ·
2
Replies
36
Views
7K
  • · Replies 6 ·
Replies
6
Views
3K