Point charges in an electromagnetic field

AI Thread Summary
The discussion revolves around calculating the tension in a string connecting two point charges in an electric field. A +8.75 micro C charge and a -6.5 micro C charge are analyzed under a uniform electric field of 1.85*10^8 N/C. The user has successfully calculated the force between the charges using Coulomb's law but is uncertain about the next steps to determine the tension in the wire. The question also explores how the tension would change if both charges were negative. Clarification on the application of electric field concepts and forces acting on the charges is needed to proceed with the solution.
nmendoza37
Messages
2
Reaction score
0
point charges in an electric field

Homework Statement


Problem: A +8.75 micro C point charge is glued to a frictionless table. It is tied to -6.5 micro C point charge by a 2.5 cm string (weightless and nonconducting). A uniform electric field of magnitude 1.85*10^8 N/C is directed parallel to the wire toward the positive charge. a) what is the tension in the wire? b) what would the tension be if both charges were negative?


Homework Equations


F=k(q1)(q2)/r^2

E(vector)= F(vector)/(q)



The Attempt at a Solution



using coloumbs law I attempted to find the force between the 2 particles. but from there i am pretty lost can anyone help?
 
Last edited:
Physics news on Phys.org
Work

q1= 8.75*10^-6 C
q2=-6.5*10^-6 C
r=.025 m

so Force=(8.988*10^9) X (q1*q2)/r^2 = 8.1*10^-4 N (q1*q2) is absolute value

but where do i go from here?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top