- #1

- 20

- 1

same i.e. 0.5 (we get this ans if we find

(dr/r) / (dl/l) ) assuming that

volume of rod always remains constant...

But why it is not so ?

We have different ratios for different materials..

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- Thread starter Prathamesh
- Start date

- #1

- 20

- 1

same i.e. 0.5 (we get this ans if we find

(dr/r) / (dl/l) ) assuming that

volume of rod always remains constant...

But why it is not so ?

We have different ratios for different materials..

- #2

- 963

- 214

same i.e. 0.5 (we get this ans if we find

(dr/r) / (dl/l) ) assuming that

volume of rod always remains constant...

But why it is not so ?

We have different ratios for different materials..

the materials try to keep their volume constant but intermolecular forces are 'realistic' forces and many a time it falls short and the ratio goes to 0.3 or such values. the hooks law which is used also can be said to be working approximations.

- #3

Chestermiller

Mentor

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For their volume to be constant, all materials would have to be incompressible.

- #4

Mapes

Science Advisor

Homework Helper

Gold Member

- 2,593

- 20

For their volume to be constant, all materials would have to be incompressible.

Not quite; they would only need to have a shear modulus of zero. A liquid would satisfy this requirement, even if it is not perfectly incompressible. You can conclude this from the identity $$\nu=\frac{3K-2G}{2(3K+G)}$$ where ##\nu## is the Poisson's ratio, ##K## is the bulk modulus, and ##G## is the shear modulus. Note that the Poisson's ratio is undefined for a perfectly incompressible material (i.e., one for which ##K=\infty##).

- #5

Chestermiller

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If the shear modulus is zero, then Young's modulus is zero, which means that, unless the Poisson ratio is equal to 1/2, the bulk modulus is zero. If the Young's modulus is not zero and the Poisson ratio is equal to 1/2, the bulk modulus is infinite, and the material is incompressible.Not quite; they would only need to have a shear modulus of zero. A liquid would satisfy this requirement, even if it is not perfectly incompressible. You can conclude this from the identity $$\nu=\frac{3K-2G}{2(3K+G)}$$ where ##\nu## is the Poisson's ratio, ##K## is the bulk modulus, and ##G## is the shear modulus. Note that the Poisson's ratio is undefined for a perfectly incompressible material (i.e., one for which ##K=\infty##).

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