Polar area between two equations

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[SOLVED] Polar area between two equations

Homework Statement



Using polar coordinates, find the area of the region shared by both curves [2cos(theta) and 2sin(theta)]


Homework Equations


.5integral((2cos(theta) - 2sin(theta))^2)dtheta)


The Attempt at a Solution



Ok. So I know what equation I have to use. I also know that one of the limits of integration will be pi/4 (the point that's not on the origin). However, I don't know what theta value represents the point on the origin. I may be doing this all wrong. Any help is appreciated.
 
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Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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