- #1
Menisto
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The problem is to find the area of the piece enclosed by the intersection of the circles r = sin t and r = cos t.
I tried to set up the integral:
Integral[0 to Pi/4]Integral[Sin[t] to Cos[t]] r dr d@
but this doesn't seem work, I get out .25, and just by eyeballing it, I can tell it is less. It seems tricky because the upper bound r = cos [t] is being traced out between the angles Pi/4 and Pi/2, while the lower bound r = sin [t] is being traced out between the angles 0 and Pi/4.
I tried to set up the integral:
Integral[0 to Pi/4]Integral[Sin[t] to Cos[t]] r dr d@
but this doesn't seem work, I get out .25, and just by eyeballing it, I can tell it is less. It seems tricky because the upper bound r = cos [t] is being traced out between the angles Pi/4 and Pi/2, while the lower bound r = sin [t] is being traced out between the angles 0 and Pi/4.
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