The problem is to find the area of the piece enclosed by the intersection of the circles r = sin t and r = cos t.(adsbygoogle = window.adsbygoogle || []).push({});

I tried to set up the integral:

Integral[0 to Pi/4]Integral[Sin[t] to Cos[t]] r dr d@

but this doesn't seem work, I get out .25, and just by eyeballing it, I can tell it is less. It seems tricky because the upper bound r = cos [t] is being traced out between the angles Pi/4 and Pi/2, while the lower bound r = sin [t] is being traced out between the angles 0 and Pi/4.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Polar Coordinants and Double Integrals

**Physics Forums | Science Articles, Homework Help, Discussion**