The problem is to find the area of the piece enclosed by the intersection of the circles r = sin t and r = cos t.(adsbygoogle = window.adsbygoogle || []).push({});

I tried to set up the integral:

Integral[0 to Pi/4]Integral[Sin[t] to Cos[t]] r dr d@

but this doesn't seem work, I get out .25, and just by eyeballing it, I can tell it is less. It seems tricky because the upper bound r = cos [t] is being traced out between the angles Pi/4 and Pi/2, while the lower bound r = sin [t] is being traced out between the angles 0 and Pi/4.

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# Homework Help: Polar Coordinants and Double Integrals

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