Polar Coordinates: Apollo 13 Reentry: Calculating Theta

Ry122
Messages
563
Reaction score
2
in this situation where apollo 13 is reentering the atmosphere, how would you determine what theta is in the polar coordinate system for velocity?

[PLAIN]http://img37.imageshack.us/img37/7366/shuttlek.jpg

Wouldn't the angle gamma be equal to theta since gamma is equal to the angle of the shuttle with the horizontal if you use the geometry postulate for opposite adjacent angles? But if this is the case then why is it labeled gamma and not theta?
 
Last edited by a moderator:
Physics news on Phys.org
Hi Ry122! :smile:

(have a theta: θ and a gamma: γ :wink:)

θ is the angle (at the centre of the Earth) between the radius where it is now and the radius where it started.

eθ is the unit vector in the θ (ie tangential) direction.

γ is just the angle between the velocity and eθ :wink:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
9
Views
2K
2
Replies
56
Views
10K
Replies
2
Views
4K
Replies
3
Views
8K
Back
Top