- #1

- 92

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## Homework Statement

## Homework Equations

r=sinx

r= cosx

Ok , i need help how to properly select the integral to evaluate the area they make. Can someone please show me how , i know how to evaluate it just having hard times with integrals

- Thread starter th3plan
- Start date

- #1

- 92

- 0

r=sinx

r= cosx

Ok , i need help how to properly select the integral to evaluate the area they make. Can someone please show me how , i know how to evaluate it just having hard times with integrals

- #2

- 208

- 0

- #3

- 92

- 0

- #4

- 1,707

- 5

first of all over what interval?

- #5

- 208

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- #6

- 92

- 0

the interval is 0,2pi

- #7

- 1,752

- 1

- #8

- 92

- 0

Calc 2

- #9

- 92

- 0

how would i change it to rectangular form, using x=rcos(theta) and y=rsin(theta)

?

?

- #10

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 956

No, it isn't. Since sine and cosine are negative for half that interval using 0 to 2[itex]\pi[/itex] gives you each circlethe interval is 0,2pi

However, you are correct that the circles intersect when tan[itex]\theta[/itex]= 1- that is, at [itex]\theta= \pi/4[/itex] as well as at 0. For [itex]0\le \theta\le \pi/4[/itex], a radius goes from 0 to cos([itex]\theta[/itex]) while from [itex]\pi/4\le \theta\le \pi/2[/itex] it goes from 0 to sin([itex]\theta[/itex]). From symmetry, you should be able to integrate cos([itex]\theta[/itex]) from 0 to [itex]\pi/4[/itex] and double.

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