Positive Charge Induction on Insulating Sphere

  • Thread starter Thread starter freeofwork
  • Start date Start date
  • Tags Tags
    Induction
AI Thread Summary
A positively charged rod can induce a negative charge on a conducting sphere placed on an insulating surface through the process of induction. The sphere becomes polarized, with negative charges moving toward the rod while positive charges are repelled, resulting in an overall negative charge on the side closest to the rod. Conduction and convection are not applicable in this scenario, as the sphere is insulated and cannot exchange charge with the rod. The discussion concludes that option d) is incorrect, as induction is indeed the correct method for this phenomenon. Understanding charge induction is crucial for grasping electrostatic principles.
freeofwork
Messages
44
Reaction score
0

Homework Statement



By what method will a positively charged rod produce a negative charge on a conducting sphere that is placed on an insulating surface.

Homework Equations



a) by means of conduction b) by means of induction c) by means of convection d) none of the choice are correct

The Attempt at a Solution



I am guessing d because the rod will only be able to polarize... and if it was conducted the negative charge would flow to the rod which will leve the sphere positive...
 
Physics news on Phys.org
really 385 views and no response...?
 
hi freeofwork :smile:

well, it's obviously not conduction or convection, and i don't think it comes within the strict definition of induction, so that does leave d) :wink:
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Understanding the Interaction Between a Charged Rod and a Metal Sphere
Replies
6
Views
2K
Work done to insert a point charge 𝑞 at the center of a conducting sphere
Replies
12
Views
1K
Electric field external to Conducting Hollow Sphere with charge inside
Replies
23
Views
3K
Intro to Electromagnetism: five conceptual questions
Replies
3
Views
2K
Electrostatics: Charging a sphere by induction
Replies
4
Views
2K
Electrostatic induction - rod and sphere
Replies
1
Views
2K
Charge on two spheres related to Earthing
Replies
17
Views
2K
How Does a Dielectric Influence Charge Induction on a Conducting Shell?
Replies
1
Views
2K
Metal sphere drawn and then repelled by charged rod
Replies
2
Views
8K
Understanding Electrostatic Charges: A Short Quiz
Replies
4
Views
6K

Hot Threads

Recent Insights

Back
Top