Possible angles for internal gravity wave propagation

AI Thread Summary
Internal gravity waves along the coast of Norway are influenced by the M2 tide with a period of 12.42 hours. The angular frequency is calculated as 1.41 x 10^-4 rad/s, while the stratification frequency is 2 x 10^-3 rad/s. Rearranging the equation for wave propagation yields potential angles of 85.96 and 94.04 degrees. The poster questions the validity of these angles, noting that a maximum of 90 degrees above the horizontal is expected. Clarification on the calculations or assumptions made is sought from other participants.
contempquant
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Homework Statement



Internal gravity waves are generated along the coast of Norway by the principal lunar semidiurnal surface tide (known as the M2 tide) of period 12.42 h. If the stratification frequency N is 2 x 10-3rad s-1, at which possible angles can the energy propagate with respect to the horizontal?

Homework Equations



\omega={\pm}Ncos{\theta}

The Attempt at a Solution



Period, T is 12.42 hours = 44712 seconds

angular frequency is \omega=\frac{2{\pi}}{T}=1.41{\times}10^{-4}

N=2{\times}10^{-3}

Rearranging \omega={\pm}Ncos{\theta} in terms of theta gives \theta=cos^{-1}{\frac{\omega}{\pm{N}}}

Giving theta values of 85.96 and 94.04, but this can't be right as i thought the maximum value of theta could be 90 degrees above the horizontal? can anyone see where I'm going wrong?
 
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