Potential and Electric Fields: Understanding Charges and Fields on a Line

In summary, a line of length L=0.950 m with uniform positive charge per unit length λ=2.9 μC has points A, B, and C located at different distances along the line. The electric field has a horizontal component at A, while at B and C it has both horizontal and vertical components. The potential at A and B are equal due to the conservative nature of Coloumbic force, while the potential at B and C are different. If the line was made of a conductor, the charges would rearrange themselves to create a zero electric field inside the conductor, according to Gauss Law.
  • #1
fogvajarash
127
0

Homework Statement


Consider a line of length L=0.950 m and uniform positive charge per unit length λ=2.9 μC. Point A is a distance x=0.23 m from the center of the line, while B is the same distance from the line but a distance y=0.28 m farther along the line; point C is a distance z=0.050 m farther along the line than B.

Answer true or false for the following statements.
a) The potential at A is higher than the potential at B.
b) The potential at B is higher than the potential at C.
c) The electric field has a horizontal component at A.
d) The electric field has a horizontal component at B.
e) The electric field has a vertical component at A.
f) The electric field has a vertical component at B.
g) If the line were made of a conductor, the charges would re-arrange themselves rather than remaining in this configuration.

Homework Equations


-

The Attempt at a Solution


I'm trying to understand how to relate potential and electric field in this situation. As we have a line, we would have that the electric field is not pointing outwards of the line, as we would only have an horizontal component in A. On the other hand, on points B, C we would have an electric field both with a horizontal and vertical component. However, I'm having trouble with the potential questions, I'm guessing that they should be equal as we do not really care about components in this case. On the other hand, I am not sure what g. is asking for.

Thank you in advance.
 

Attachments

  • Image (2).jpg
    Image (2).jpg
    7.1 KB · Views: 365
Physics news on Phys.org
  • #2
First, let us talk about option 'g' since it is easy. Have a look a Gauss Law : http://en.wikipedia.org/wiki/Gauss's_law
(Hint: Field inside a conductor must be zero). Now relate charge distribution of the rod with Gauss Law to make the field inside zero.

Then, coming to potentials, I guess you have a problem regarding the first two options. The basic definition of change in electric potential is -∫E.dr(mind the negative sign). Coloumbic force is a conservative one. So it doesn't matter how you reach point b. Now, try reaching the point B by first reaching point 'A' and then climbing upwards. Also take care of the point that, while climbing upwards, bother only about the vertical components (Think why?).

Think about it; do inform me if you have any problem.

Regards
ADI.
 

1. What is an electric field?

An electric field is a region in space around a charged object where other charged particles will experience a force. This force can either attract or repel the charged particles depending on the sign of their charge.

2. What is the difference between potential energy and electric potential?

Potential energy is the stored energy of a system due to the position or configuration of its objects. Electric potential, on the other hand, is the amount of potential energy per unit charge at a point in an electric field. In other words, electric potential is a measure of how much work would be required to move a unit of charge from one point to another in an electric field.

3. How is electric potential calculated?

Electric potential is calculated by dividing the potential energy by the charge. The formula for electric potential is V = U/q, where V is the electric potential, U is the potential energy, and q is the charge.

4. What is the relationship between electric field and electric potential?

Electric field and electric potential are directly related. The electric field is the negative gradient of the electric potential, meaning that the direction of the electric field points in the direction of decreasing potential. In other words, the electric field is the rate of change of electric potential in a given direction.

5. How do electric fields affect the motion of charged particles?

Charged particles will experience a force when placed in an electric field, causing them to accelerate. The direction of this acceleration will depend on the direction of the electric field and the charge of the particle. In a uniform electric field, the charged particle will experience a constant acceleration, whereas in a non-uniform electric field, the acceleration will vary at different points.

Similar threads

  • Introductory Physics Homework Help
Replies
1
Views
787
  • Introductory Physics Homework Help
Replies
1
Views
249
  • Introductory Physics Homework Help
Replies
5
Views
807
  • Introductory Physics Homework Help
Replies
6
Views
920
  • Introductory Physics Homework Help
Replies
12
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
28
Views
576
  • Introductory Physics Homework Help
Replies
9
Views
260
Back
Top