- #1
omarMihilmy
- 31
- 0
My problem is with the solution
If we differentiate:
dU/dx = 9x^2 - 7
From where does the negative come from also the j component?
Potential Energy: Differentiating to Find Force
- Thread starter omarMihilmy
- Start date
AI Thread Summary
To find the force from potential energy, the correct approach is to differentiate the potential energy function U with respect to position x, yielding dU/dx = 9x^2 - 7. Concerns were raised about the presence of the negative term and the j component in the differentiation. The relevant equation for force derived from potential energy is F = -dU/dx, indicating that the force is the negative gradient of potential energy. Additionally, it was noted that the y-component should not be disregarded during differentiation. Clarification on these points is essential for accurate problem-solving in physics.
My problem is with the solution
If we differentiate:
dU/dx = 9x^2 - 7
From where does the negative come from also the j component?
- #2
voko
- 6,053
- 391
You should have used the homework template, then you have written the relevant equations. What equation is relevant for finding force from potential energy?
- #3
omarMihilmy
- 31
- 0
F = dU/dx
- #4
voko
- 6,053
- 391
That is not correct.
- #5
omarMihilmy
- 31
- 0
Correct me if I am wrong
- #6
shanname
- 8
- 0
Why are you disregarding the y-component when you differentiate?
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler:
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