Potential From an Electric Field

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SUMMARY

The discussion focuses on calculating the potential difference in a uniform electric field of 8 kN/C in the x direction, specifically between the points at 0 m and 4 m. The user initially attempted to compute the potential difference using the integral \(\int -E \cdot dl\), resulting in -E*4, but did not account for the influence of the point charge Q = 3 micro Coulombs. It is established that the potential difference depends solely on the electric field and not on the charge itself.

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snoweangel27
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I have been trying to calculate the potential difference between to points. In doing so, I have tried taking [tex]\int[/tex] -E * dl, in which I end up with -E*4, but that does not include the point charge, and I'm just not sure what I need to do to Calculate the potential with the addition of the point charge.

Question
A uniform electric field of 8 kN/C is in the x direction. A positive point charge Q = 3 micro Coloumbs is released from rest at the origin.
--What is the potential difference V(4 m) - V(0)?
 
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You're doing OK. The potential difference only depends on the field, not on the charge you are putting in the field. (I suspect there will be addition questions for this problem where you will need to use the charge.)
 

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