What is the speed as it hits the wheel?

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The discussion focuses on calculating the maximum power output of a water wheel receiving water from a height of 2.0 meters at a rate of 95 kg/s. The gravitational potential energy (GPE) of the falling water is converted into kinetic energy (KE) as it hits the wheel. The relationship between GPE and KE is established through the equations mgh and 1/2 mv^2, indicating that energy is conserved during the fall. The power output can be determined using the mass flow rate and the height, leading to the conclusion that the rate of energy delivery is given by the formula \dot{m}gh. Understanding these principles allows for the calculation of both the maximum power output and the speed of water as it impacts the wheel.
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Homework Statement


Water falls onto a water wheell from a height of 2.0m at a rate of 95kg/s (a) If this water wheel is set up to provide electricity output, what is the max power output. (b) What is the speed as it hits the wheel?


Homework Equations



Ep= mgh Ek= 1/2mv^2

The Attempt at a Solution



I know that the water initally has both potential and kinetic energy as it falls but i am unsure as to how i use the rate in these equations and also which power equation(s) I use once i get to that stage.
 
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Well the elevation of a mass m in a gravitational field provides for gravitational potential energy (GPE) by virtue of mgh, where h is the elevation above some reference point.

If an object at h is released and it falls through distance h, then GPE decreases by mgh and that GPE is transformed to kinetic energy 1/2 mv2, and neglecting air resistance mgh = 1/2 mv2.

If one has a mass flow rate \dot{m}, then the rate at which energy (described above) is delivered is simply \dot{m}gh, and the rate of energy delivery/transformation is power.
 
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