Power particle-like object problem

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The discussion revolves around calculating the instantaneous power exerted on a particle-like object under a specific force and velocity. The force is given as F = (5.0 N) i - (1.0 N) j + (10.0 N) k, while the velocity is v = - (2.0 m/s) i + (4.0 m/s) k. The user initially attempted to find the power by taking the dot product of the force and velocity but arrived at an incorrect result of 41.2 Watts. Other participants clarified that the dot product alone is sufficient for the first part, and for the second part, they suggested setting the velocity to only the j component and equating the product to the given instantaneous power of -12 W. The conversation emphasizes the importance of correctly applying the dot product and understanding the relationship between force, velocity, and power.
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Hi, I've been trying to complete this question for almost an hour, i was hoping you could provide some advice

At a certain instant, a particle-like object is acted on by a force F = (5.0 N) i hat - (1.0 N) j hat + (10.0 N) k hat while the object's velocity is v = - (2.0 m/s) i hat + (4.0 m/s) k hat. 1)What is the instantaneous rate at which the force does work on the object?

2)At some other time, the velocity consists of only a j component. If the force is unchanged, and the instantaneous power is -12 W, what is the velocity of the object just then?

I tried taking the dot product of the force and velocity, making sure i only multiplied the like terms of the unit vectors. then i took the hypotenuse using pythagoras, but the answer i get is 41.2 Watts and its not right? please could someone help?
 
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critch said:
I tried taking the dot product of the force and velocity, making sure i only multiplied the like terms of the unit vectors. then i took the hypotenuse using pythagoras, but the answer i get is 41.2 Watts and its not right? please could someone help?

1) Taking the dot product is enough. I didn't quite understand what you have done after that.

2) Suppose the velo is v = vj. Find F.v and equate it to the instantaneous power given.
 
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