Power series to solve 2nd order ordinary differential equations

hbomb
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I need some help with power series.
I can't remember how to find a power series center around a point.
example question:
y"-xy'-y=0, x=1
I don't how to start this.
 
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hbomb said:
I need some help with power series.
I can't remember how to find a power series center around a point.
example question:
y"-xy'-y=0, x=1
I don't how to start this.

You should find this link useful: http://tutorial.math.lamar.edu/AllBrowsers/3401/SeriesSolutions.asp" .
 
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Yes, thanks. The site has been helpful, but I have a question that I couldn't find an answer for. What happens if you have a summation with the starting index of the summation with n=0 but one of the summations you have an index of n=1. All the exponents are the same.

Also what happens if instead x=1?
 
If you start at n =1, you subtract 1 from the exponent. So:

\sum_{n=0}^{k} x^{n} = \sum_{n=1}^{k}x^{n-1}
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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