Poynting Vector - Finding stored energy per unit length of a solenoid

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SUMMARY

The discussion focuses on calculating the rate of increase of stored energy per unit length in a solenoid using three distinct methods: inductance, energy associated with fields, and the Poynting vector. The solenoid has n turns per unit length and a cylindrical core of radius a, with a current I that increases at a constant rate dI/dt. Key equations derived include the inductance L = μn²lA and the energy U = ∫B²/2μ dv, leading to U/dt = μn²lA (dI/dt) I (1/2). The participant expresses confusion regarding the presence of an electric field within the solenoid and the correct application of the Poynting vector.

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  • Understanding of Ampere's Law and its application in electromagnetism
  • Familiarity with the concept of inductance and its formula L = μn²lA
  • Knowledge of the Poynting vector and its relation to electromagnetic fields
  • Basic calculus for integration of energy density over a volume
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Homework Statement



long solenoid of n turns per unit length is wound upon a cylindrical core of radius a
and relative permeability. The current I through the solenoid is increasing with time t at a
constant rate. Obtain expression for the rate of increase of stored energy per unit length in the core
of the solenoid
(a) from the inductance per unit length of the solenoid, and dI=dt.
(b) from the energy associated with the fields internal to the solenoid core.
(c) by integration of the Poynting vector over an appropriate surface.

Homework Equations



None are given but I believe this is what should be considered:

-∂/∂t ∫[ εE2/2 + B2/2μ ] dv = ∫ Jf dot E dv + ∫ E cross H da

Ampere's Law

E cross H = S

The Attempt at a Solution



Using Ampere's Law: B=μnI

L = flux/I
L = μn2lA Where l is some length and A is a surface


Part A)

∅ = L dI/dt

∅ = μn2lA dI/dt

U = Q∅/2

U/dt = μn2lA (dI/dt) (Q/dt) (1/2)

U/dt = μn2lA (dI/dt) I (1/2)

This just does not seem right to me??

Part B)

U = ∫B2/2μ dv

U = ∫(μnI)2/2μ dv

U = μn2lAI (1/2)

U/dt = μn2lA (dI/dt) I (1/2)

Part C)

U = ∫ S dv

where S = E cross H, assuming ∫ Jf dot E dv = 0

This is where I am confused. Is there an electric field in the solenoid? If so then did I not do the other parts correctly? What am I missing here...
 
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Not that complicated. Given inductance L, what is the formula for stored energy?

Then, calculate L per unit length.
 

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