- #1
recreated
- 50
- 1
If you wanted to calculate the pressure on the shell of an airtight enclosed concentric or asymmetrical/symetrical object, do you simply need the surface area of the object and then divide it into the applied force?
1. So if you apply 50Newtons onto a grounded football for example,it would be... (Force)/(4.pie.radius)>>>>surface area of the football...? And what if the football had an inch thick shell, would I need the surface area on the inner or outer of the shell? Correct me, but I assume its all about surface area and that shape wouldn't make a difference...
...but does thickness make a difference...?
2. I am trying to figure out the pressure on the walls of a exhaust powered car jack, it's basically an inflatable cylinder(although when inflated it asymmetrical as it bulges). The one I am trying to design will have plates on top and bottom, so how would the variation in surface thicknesses affect the spread of pressure?
May help:
Pressure = Force/Area
surface area of cylinder = 2.pie.r(r + h)
Thanks,
James
Oh and have a look on google images for exhaust powered car jack if it will help.
1. So if you apply 50Newtons onto a grounded football for example,it would be... (Force)/(4.pie.radius)>>>>surface area of the football...? And what if the football had an inch thick shell, would I need the surface area on the inner or outer of the shell? Correct me, but I assume its all about surface area and that shape wouldn't make a difference...
...but does thickness make a difference...?
2. I am trying to figure out the pressure on the walls of a exhaust powered car jack, it's basically an inflatable cylinder(although when inflated it asymmetrical as it bulges). The one I am trying to design will have plates on top and bottom, so how would the variation in surface thicknesses affect the spread of pressure?
May help:
Pressure = Force/Area
surface area of cylinder = 2.pie.r(r + h)
Thanks,
James
Oh and have a look on google images for exhaust powered car jack if it will help.