If you wanted to calculate the pressure on the shell of an airtight enclosed concentric or asymmetrical/symetrical object, do you simply need the surface area of the object and then divide it into the applied force? 1. So if you apply 50Newtons onto a grounded football for example,it would be.... (Force)/(4.pie.radius)>>>>surface area of the football.....??? And what if the football had an inch thick shell, would I need the surface area on the inner or outer of the shell? Correct me, but I assume its all about surface area and that shape wouldn't make a difference... ...but does thickness make a difference...? 2. I am trying to figure out the pressure on the walls of a exhaust powered car jack, it's basically an inflatable cylinder(although when inflated it asymmetrical as it bulges). The one I am trying to design will have plates on top and bottom, so how would the variation in surface thicknesses affect the spread of pressure? May help: Pressure = Force/Area surface area of cylinder = 2.pie.r(r + h) Thanks, James Oh and have a look on google images for exhaust powered car jack if it will help.