Pressure in water and different liquid

AI Thread Summary
The discussion revolves around calculating pressure and buoyant force for submerged wooden blocks. The initial approach used the pressure formula but shifted focus to buoyant force, emphasizing that it equals the weight of the liquid displaced. Participants clarified that the buoyant force should be calculated using the volume of the submerged part of the block and the density of the liquid. There was confusion regarding the variables in the equations, particularly the density and volume used in calculations. Ultimately, the correct approach involves balancing the weight of the block with the buoyant force for equilibrium.
Scarlet_pat
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Homework Statement


consider the figures 1 and 2 which show two identical, rectangular wooden blocks

Weight of the block:



Homework Equations



Pressure = F/a
Pressure = Density x gravity x height



The Attempt at a Solution



The weight of the block,
i have tried to find the pressure of water of figure1

pressure = p g h = p = 1000 x 9.8 x 0.05 = 490 N/m^2

but i do not have any idea of what to do after.

thank you very much
 

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There is no need for finding pressure. Find the buoyant force
 


the buoyant force = V p g ...
the buoyant force = to the force exerted by the object.
therefore times the buoyant force by two, Because it is exact half submerged ?
 
Hi Scarlet_pat! :smile:

(have a rho: ρ :wink:)
Scarlet_pat said:
the buoyant force = V p g ...
the buoyant force = to the force exerted by the object.
therefore times the buoyant force by two, Because it is exact half submerged ?

Yes, but that's no way to prove it :redface:

you need to write an equation, weight + buoyant force = 0.

(btw, you could have used pressure … the upward force from the water is the pressure times the area of the base … but buoyant force is more sensible :wink:)
 


thank you very much for comfirming my answer :)
i was actually try to the method you have just suggested.
F= Pa = p g h * A

the the pressure there is always referring to Pressure of liquid right ?

however i think i have made a mistake ...
for F= V p g <-- the volume should be the volume of the object which submerged in the liquid right ?
 
Scarlet_pat said:
for F= V p g <-- the volume should be the volume of the object which submerged in the liquid right ?

(What happened to that ρ I gave you? :confused:)

I'm confused …

is ρ here the density of the block or of the water, and is this supposed to be the buoyant force or the weight?
 


lets just stick to the first equation ;)
F = V p g

and what I'm wondering is F = upthrust ,
V = volume of object submerged in liquid OR volume of the block?
p = density of liquid
g = acceleration due to gravity

am i right ?
 
The upthrust is the weight of the liquid displaced, which is the density of the liquid times the volume of the liquid displaced (ie the volume of the object submerged). :smile:
 


ok thanks ... thank you. ill have to time the upthrust by 2, because the object is only half submerged ... right ?
 
  • #10
The upthrust is the upthrust, you don't "times" it by anything, you add it to the weight to get zero.
 
  • #11


ok thanks. :)
 
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