Pressure issue on pipeline splitting

  • Thread starter Thread starter HoBBLeCooKiE
  • Start date Start date
  • Tags Tags
    Pressure Splitting
AI Thread Summary
When dealing with a pump system that splits into two pipes, the required pressure at each outlet does not necessitate doubling the pressure in the total head calculation. For a system requiring 140 kPa (equivalent to 14.27m) at each cyclone, only one instance of this pressure needs to be added to the total head, along with other losses from friction, bends, and valves. The pressure loss due to flow will be equal across both pipes in parallel, simplifying the calculation. It's important to consider the total head as the sum of physical height and all head losses, excluding the need to account for the split pressure twice. Thus, the total head required is the physical height plus the cumulative head losses, plus the pressure needed at the exit, calculated only once for the split.
HoBBLeCooKiE
Messages
9
Reaction score
0
Can anyone give me some assistance on this problem:

I have a pump below a sump of 1m high and pumping upward in a pipe that splits near the end.
I require at least 140kPa pressure on EACH pipe. I know I need to enter the pressure in terms of head into the total head (physical height - suction height + total head loss) required, but what happens with the split? Do I add 140kPa to the total head required, or do I add (2 x 140kPa)?

Thanks!
 
Engineering news on Phys.org
The pressure in the pipes will be determined by the discharge conditions, pipe material, pipe size and geometry, any valves, etc. But to answer your question, it's just the 140 kPa.

What do you mean, though, by "add 140 kPa to the total head required"? Are you sizing the pump?
 
Without flow, you don't have to add anything for the split, just height is relevant (you can imagine a single pipe as many pipes right next to each other if you like, it does not change the result). With flow, it depends on the pressure loss due to the flow.
 
I guess I didn't explain clearly...sorry about that.
I have a pipe system that runs from the pump 8m up to 2 cyclones. The total head would be the 8m + headloss due to friction + headloss due to split + headloss due to any bends, valves, enlargements, etc. + head needed at exit. I need 140kPa (14.27m) in each cyclone. Do I need to add the 14.27m once to the rest of the head loss and height or do I need to add it for each cyclone? I know in parallel pipes the headloss is equal across each pipe, just scratching my head over the pump pumping into the cyclones.
 
Yep, just add it the once.
 
Thread 'Turbocharging carbureted petrol 2 stroke engines'
Hi everyone, online I ve seen some images about 2 stroke carbureted turbo (motorcycle derivation engine). Now.. In the past in this forum some members spoke about turbocharging 2 stroke but not in sufficient detail. The intake and the exhaust are open at the same time and there are no valves like a 4 stroke. But if you search online you can find carbureted 2stroke turbo sled or the Am6 turbo. The question is: Is really possible turbocharge a 2 stroke carburated(NOT EFI)petrol engine and...
I need some assistance with calculating hp requirements for moving a load. - The 4000lb load is resting on ball bearing rails so friction is effectively zero and will be covered by my added power contingencies. Load: 4000lbs Distance to travel: 10 meters. Time to Travel: 7.5 seconds Need to accelerate the load from a stop to a nominal speed then decelerate coming to a stop. My power delivery method will be a gearmotor driving a gear rack. - I suspect the pinion gear to be about 3-4in in...
Back
Top