Pressure of piston in a cylinder containing gas, find heat (Q)

AI Thread Summary
The discussion revolves around calculating the heat absorbed (Q) by an ideal gas in a cylinder as it expands and pushes a piston to a new height (H) while increasing its temperature from T to 2T. The user attempts to derive the change in internal energy (ΔU) and relates it to heat and work using the equations provided. They express ΔU in terms of the number of gas molecules (N), Boltzmann's constant (KB), and the initial and final temperatures. The user also considers the forces acting on the piston, including atmospheric pressure and the weight of the piston, to formulate the work done by the gas. The discussion highlights the need for clarification on the calculations and the approach to solving the second part of the problem.
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Homework Statement


A cylinder of cross-sectional A is filled with N ideal gas molecules at temperature T and pressure p, and a piston of mass m seals the gas in the cylinder with a frictionless seal, as shown on the figure attached. The trapped column of gas has an initial height h. The piston and cylinder are surronded by air at pressure patem. A) How much heat Q does the gas absorb if it ends up at temperature 2T and pressure p after expanding and pushing the piston to a final height H? B) What is the final height H of the piston as some multiple of h. Note that the piston is at rest when the heating starts and is at rest when it reaches its final height H. Your answer to (A) should be expressed in terms of the quantities h, g, A, m, and patm. Please be careful when calculating the work done by the expanding gas on its surrondings.


Homework Equations



Change in internal energy (U) equation: ΔU=Uf-Ui

Internal energy equation to heat (Q) and work (W): U = Q-W

Force of a gas equation to pressure (p) and cross-sectional area (A): F=P*A

Work equation to pressure (p) times the change in volume (ΔV): W = PΔV





The Attempt at a Solution



I think I have an answer for part A:

I drew in the forces on the attached document.

For finding U:

U = 3/2NKBT

Initial T=T

Final T=2T

So for U, we have:

ΔU=Uf-Ui =

3/2NKB2T-3/2NKT = 3/2NKBT = U

F=P*A: -mg+p=patm*A

V=Δh(?) = H-h

So:

Q=U+W:

Q= (3/2NKBT+mg+p-patm*A*(H-h)

I'm guessing this isn't completely correct but if someone could let me know, that would be great. Otherwise, I have no idea how to do the second part to this problem.
 
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Ok here, much bigger.
 

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