Does Curved Surface Shape Affect Pressure Distribution?

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The discussion focuses on whether the shape of a curved surface affects pressure distribution and the role of forces between atoms. Participants clarify that pressure acts uniformly in all directions, regardless of surface curvature, and that the concept of "red force" refers to the interactions between neighboring atoms. It is emphasized that while these atomic interactions can create surface tension, they do not alter the fundamental pressure experienced by a surface. The conversation also touches on how pressure in a liquid is consistent and not influenced by the shape of the container. Ultimately, it concludes that pressure remains constant and is not concentrated by varying surface shapes.
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For compute force from pressure on a surface, do I need take in account the red force ? When an atom press a surface it press atoms at right and at left, this increase the pressure on the curved surface if the volume is closed ?

http://imageshack.us/a/img823/3852/66o4.jpg

Or temperature cancel red forces ?
 
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I do not understand the question. What is the red force?
 
What is your boundary line?
A continuous distribution of micro-atoms??
 
I consider the pressure come from top, like an object is in water (but liquid can be another than water).

mikeph said:
I do not understand the question. What is the red force?
The red force come from left and right atoms that compress atom. An atom receive pressure from top (in a liquid under gravity like you put an object in a swimming pool). But atom receive pressure from another atoms in the same depth (black arrows) this give red force.

Boundary line is the surface. A circle is an atom.

http://imageshack.us/a/img31/3277/o3qc.jpg
 
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mikeph said:
I do not understand the question. What is the red force?

As I read the drawing, he has the atom on the lower left pushing upward and right on the atom in the middle. The force on the atom in the middle is represented by the upward-and-right pointing black arrow. Similarly, the atom on the upper right is pushing downward and left on the atom in the middle with its force represented by the downward-and-left pointing black arrow.

The two black forces are nearly equal and opposite. But not quite. Their vector sum is the outward-pointing red arrow.

As Arildno seems to be suggesting, perhaps this is a depiction of a cylindrical single-atom-thick shell under pressure.
 
gravity is perpendicular to the screen, like that it's easier to understand for me. If radius of atom is divided by 2, the angle decrease, the red force too but the number of red forces increase too.
 
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The pressure at a "point" in a liquid is the same in all directions. No?
 
CWatters said:
The pressure at a "point" in a liquid is the same in all directions. No?

Pressure doesn't have a direction.
 
Gh778 said:
For compute force from pressure on a surface, do I need take in account the red force ? When an atom press a surface it press atoms at right and at left, this increase the pressure on the curved surface if the volume is closed ?

Yes the force between neighbor atoms creates a surface tension and that tension creates a pressure difference between the inside and the outside of the droplet due to the curvature of the surface.

Or temperature cancel red forces ?

Temperature's got nothing to do with it.
 
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  • #10
1/ This would say the pressure on a dam http://en.wikipedia.org/wiki/Dam is bigger due to these forces ?

2/ If I place a tube full of liquid like the image show:

http://imageshack.us/a/img801/3471/3btm.jpg

Red forces in the curvature are canceled by axis. But like sum of forces of all the tube is always zero, there are Fa and Fb forces. How the sum of torque can be to zero ?
 
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  • #11
Gh778 said:
1/ This would say the pressure on a dam http://en.wikipedia.org/wiki/Dam is bigger due to these forces ?

The curvature of the dam is too large to have an effect. This effect is noticeable in cloud droplets which have microscopic curvature radii.

2/ If I place a tube full of liquid like the image show:

http://imageshack.us/a/img801/3471/3btm.jpg

Red forces in the curvature are canceled by axis. But like sum of forces of all the tube is always zero, there are Fa and Fb forces. How the sum of torque can be to zero ?

The forces in the curved part of the tube will not be exactly axial
 
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  • #12
The forces in the curved part of the tube will not be exactly axial

It's because the pressure of layer just above is lower ?

And what's cancel torque from Fb/Fa ?

Maybe it's easier with a square section.
 
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  • #13
Gh778 said:
For compute force from pressure on a surface, do I need take in account the red force ? When an atom press a surface it press atoms at right and at left, this increase the pressure on the curved surface if the volume is closed ?
The pressure is the pressure. It is what it is and isn't two different pressures at once. It does not get concentrated or focused by varying the shape of the container. This is a basic principle of how pressure works. And I'm quite sure we've explained this to you before.

Thread locked.
 
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