How Do Two Superposed Waves Result in Points of Zero Displacement?

AI Thread Summary
The discussion focuses on deriving the resultant displacement from two superposed waves, given by the equations y1=Ysin(kx-wt) and y2=Ysin(kx+wt). The resultant displacement is expressed as y=2Ysin(kx)cos(-wt). To find points of zero displacement, it is established that displacement is zero when sin(kx)=0, which occurs at x=nπ/k, where n is an integer. The clarification confirms that x=0 is not the only solution for zero displacement; rather, it occurs at multiple points defined by the integer multiples of π/k. Understanding these points is crucial for analyzing wave interference patterns.
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Homework Statement


given 2 waves y1=Ysin(kx-wt): y2=Ysin(kx+wt).
derive expression of resultant displacement and expression of x(for resultant) where displacement always zero


Homework Equations


y=y1+y2
sinA+sinB=2sin((A+B)/2)cos((A-B)/2)


The Attempt at a Solution


i solved first part:y= 2Y sin (kx) cos (-wt)
but i don't understand the 2nd part. does it mean y=0 when sin kx=0? mean x=0?
 
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Is x = 0 the only value of x at which sin(kx) = 0?
 
I had figure it out.displacement is directly related to sin kx.displacement is Zero when kx equal to n*pai
where n is integer.displacement always zero when x = n*pai/k.
 
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