(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

3. The attempt at a solution

I think I'm just evaluating integrals in this problem, not so? For part a)

[itex]\int_0 ^1 λe^{-λt}dt = \int_0 ^1 e^{-t}dt = -e^{-t} |^1 _0 = \frac{-1}{e} + 1[/itex]

For part b)

[itex]\int_0 ^3 e^{-t}dt = -e^{-t} |^3 _0 = \frac{-1}{e^3} + 1[/itex]

For part c)

[itex]\int_3 ^4 e^{-t}dt = -e^{-t} |^4 _3 = \frac{-1}{e^4} + \frac{1}{e^3}[/itex]

For part d)

Consider the limit as R goes to ∞ of [itex]\int_4 ^R e^{-t}dt = -e^{-t} | ^R _4 = 0 + \frac{1}{e^4}[/itex]

Does that seem right?

**Physics Forums - The Fusion of Science and Community**

# Probability Density Functions

Have something to add?

- Similar discussions for: Probability Density Functions

Loading...

**Physics Forums - The Fusion of Science and Community**