PROBABILITY: Distribution function

Click For Summary
SUMMARY

The discussion focuses on determining the distribution function FX for a continuous random variable X with the density function f(x) = ax²(1 - x) for 0 < x < 1. The constant a is calculated using the normalization condition ∫ f(x) dx = 1. Participants also explore how to compute the expectation E(X), variance Var(X), and the conditional probability p(X < 1/2 | X > 1/4) using standard statistical formulas.

PREREQUISITES
  • Understanding of continuous random variables
  • Knowledge of probability density functions (PDFs)
  • Familiarity with integration techniques
  • Basic concepts of expectation and variance in probability theory
NEXT STEPS
  • Study the derivation of normalization conditions for probability density functions
  • Learn about calculating expectation and variance for continuous random variables
  • Research conditional probability and its applications in statistics
  • Explore the properties of polynomial functions in probability distributions
USEFUL FOR

Students in statistics or probability courses, educators teaching probability theory, and anyone interested in understanding continuous random variables and their properties.

tamintl
Messages
74
Reaction score
0

Homework Statement


A continuous random variable X has density f(x) = ax2(1- x) for 0 < x < 1, and
f(x) = 0 otherwise. Here a is a constant, to be determined. Find the distribution func-
tion FX, the constant a, the expectation E(X), the variance Var(X), and the conditional
probability p(X < 1/2 | X > 1/4)



Homework Equations





The Attempt at a Solution


Really don't know where to start
 
Physics news on Phys.org
Start by using the fact that
[tex]\int_{-\infty}^\infty f(x)\,dx=1[/tex]
to figure out a. Then use the standard formulas.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
7
Views
1K
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
9
Views
3K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
9
Views
4K