Problem on the transfer of heat into different materials

  • Thread starter Thread starter lemonbrook
  • Start date Start date
  • Tags Tags
    Heat Materials
Click For Summary
SUMMARY

The discussion focuses on estimating the depth at which a temperature of 723K would be reached in a titanium alloy specimen after 3 seconds of immersion in a liquid salt bath at 773K. Key thermal properties are provided: titanium has a thermal conductivity of 6 W m-1 K-1 and a specific heat capacity of 500 J kg-1 K-1. The relevant equation for heat transfer is identified as the rate of heat flow, incorporating thermal conductivity and temperature difference. The thermal diffusivity approach, L2/D, is suggested for estimating the time required for temperature propagation.

PREREQUISITES
  • Understanding of thermal conductivity and its units
  • Familiarity with specific heat capacity and density concepts
  • Knowledge of heat transfer equations and thermal diffusivity
  • Basic algebra for rearranging equations
NEXT STEPS
  • Research the calculation of thermal diffusivity for different materials
  • Learn how to apply the heat transfer equation in practical scenarios
  • Explore the effects of material properties on heat transfer rates
  • Investigate numerical methods for solving heat transfer problems
USEFUL FOR

Students and professionals in materials science, thermal engineering, and physics who are interested in heat transfer analysis and material property applications.

lemonbrook
Messages
2
Reaction score
0
Hi all,

1. The problem statement

A copper specimen, initially at 293K, is immersed in a bath of liquid salt at 773K. The bath is agitated and the heat transfer at the surface of the metal is effectively perfect. A temperature of 723K is measured at 5mm below the surface of the metal item after 3 seconds. Estimate the depth below the surface at which a temperature of 723K would be reached in 3 seconds if the specimen were made of titanium alloy.

Copper

Thermal Conductivity = 380 W m-1 K-1
Specific Heat Capacity = 390 J kg-1 K-1
Density - 8900 kg m-3

Titanium

Thermal Conductivity = 6 W m-1 K-1
Specific Heat Capacity = 500 J kg-1 K-1
Density - 4500 kg m-3

Homework Equations



This equation wasn't given in the question but seems to be relevant.

8ff29039f45e4bd1e41276b599137007.png


where
fb5544db7cc3913abfb5d87fc35a6207.png
is the rate of heat flow, k is the thermal conductivity, A is the total cross sectional area of conducting surface, ΔT is temperature difference, and x is the thickness of conducting surface separating the 2 temperatures.

The Attempt at a Solution



I'm very confused as to how to approach this problem. I first attempted to rearrange the equation for Area, but I would also need to have ΔQ which would require a mass to calculate. Could I just use and arbitrary volume for both components and use the density to calculate a mass?

Thanks
 
Physics news on Phys.org
Hi lemonbrook, welcome to PF. A common way of estimating the required time for a temperature change to propagate a distance [itex]L[/itex] is [itex]L^2/D[/itex], where [itex]D[/itex] is the material's http://en.wikipedia.org/wiki/Thermal_diffusivity" .
 
Last edited by a moderator:
That it!

Thanks very much!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
25
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
9
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K