Problem with finding angle using dot products

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To find the cosines of the internal angles of a triangle defined by vertices A(4,0,2), B(6,2,1), and C(5,1,6), it is essential to correctly identify the vectors representing each side. For calculating the cosine of the angle at vertex B, one can use either vectors AB and BC or BA and BC, but consistency in the order of the vectors is crucial. The dot product should be computed such that the same vertex is positioned at the start or end of both vectors to ensure accurate results. This approach will yield a positive value for acute angles and a negative value for obtuse angles. Following this method will clarify which vectors to use and help avoid confusion in calculations.
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Homework Statement


Find the cosines of the internal angles of the triangle which has the following coordinate vectors as its vertices: A(4,0,2) B(6,2,1) C(5,1,6)


Homework Equations



I understand that you have to find the 3 vectors which represents each side of the triangle in order to get the cosine.

My problem is, which vectors do I use for each angle? Let's say that I want to find the cosine of the angle at vertex B. Do I use vector AB and BC or do I use BA and BC? When I use AB(b-a=(2,2,-1)) and BC(c-b=(-1,-1,5)) the dot product of the vectors are negative whereas when I use BA and BC its positive hence I get different answers. Which one do I use and why?
 
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You should order the dot product so that the same vertex comes at the start or end of both vectors. So either AB.AC or BA.CA is OK to find the cosine of the angle at vertex A. To avoid confusion, I'd say just stick with the first "rule" (make sure the first letters are the same).

This will give you a positive value if the internal angle is acute, and a negative value if the internal angle is obtuse.
 
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