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Projectile Motion: Firing range

  1. Sep 5, 2015 #1
    1. The problem statement, all variables and given/known data

    The problem and all known information is attached.

    2. Relevant equations
    The kinematic equations are attached.

    3. The attempt at a solution
    My attempt is attached. I did part (a), (b), and (c), right.

    How do I do part (d)? I tried distance/ time .
     

    Attached Files:

  2. jcsd
  3. Sep 5, 2015 #2
    Maybe you can find its vertical and horizontal velocity at that time, then you can reach the goal. Since you have done the first three problems, this couldn't be complicated for you. Give it a try!
     
  4. Sep 5, 2015 #3
    Thanks for reply. Its the easiest question but I don't see it. I tried a few a things before you commented.

    Can you explain why is it 28.9 m/s?
     
    Last edited: Sep 5, 2015
  5. Sep 5, 2015 #4
    I will help. Just give me a sec to read the question.
     
  6. Sep 5, 2015 #5
    You are given the initial vertical and horizontal velocity ##v_v=v_0\sin\theta## and ##v_h=v_0\cos\theta## and the vertical acceleration ##a=-g.## Because ##v_h## remains constant, so when ##t=1.5,## ##v_h=v_0\cos\theta## and ##v_v=v_0\sin\theta+at=v_0\sin\theta-1.5s\cdot g.## This can give you any idea?
     
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