Projectile Motion Problem: Calculating Horizontal Distance with d=s*t Formula

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To solve the projectile motion problem, the formula d = s * t is used, where d is the horizontal distance, s is the horizontal velocity, and t is the time of fall. In this case, Harry's horizontal velocity is 70 m/s, and he falls for 3 seconds. By applying the formula, the horizontal distance traveled is calculated as d = 70 m/s * 3 s, resulting in 210 meters. The discussion emphasizes the importance of understanding the relationship between velocity, time, and distance in projectile motion. This approach clarifies how to determine the distance traveled during free fall without air resistance.
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Problem: Harry accidentally falls out of a helicopter that is traveling horizontally at 70 m/s. He plunges into the water below 3 seconds later. Assuming no air resistance, what is the horizontal distance he travels while falling?

why would you use the formula d= s*t ?

Please help i really don't understand!
 
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You are given a horizontal velocity, and a time. You need to find the distance traveled.

Have you thought about this for any length of time?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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