Projectile motion tennis ball problem

AI Thread Summary
To solve the projectile motion problem of a tennis ball hit with vertical and horizontal speeds of 10 m/s and 30 m/s, respectively, the time the ball remains in the air can be calculated using kinematic equations. The vertical motion is analyzed with the equation d = v1*t + (1/2)at^2, where the initial vertical velocity is 10 m/s and acceleration due to gravity is -9.8 m/s². The time to reach the highest point is found using v = u + at, and this time is doubled to find the total air time, which is 2 seconds. The horizontal distance traveled during this time is calculated using s = ut, resulting in a total horizontal distance of 60 meters. The angle of projection is not necessary for these calculations since both vertical and horizontal components are provided.
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Homework Statement


Tennis Ball hit at a vertical speed of 10 m/s & Horizontal speed of 30 m/s. How long will the ball remain in the air? How far will the ball travel horizontally?


Homework Equations


I am not sure which equation to use? The angle that the ball was hit is not given, would I try all angles? 30,37,45,57,60? I know that 45 would give the max distance


The Attempt at a Solution


Answers given:
How far: 60m
How long: 2s

Thanks!
 
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To find how long the ball is in the air, use the equation:

d = v1*t + (1/2)at^2. apply this equation for vertical displacement...
 
As vertical and horizontal components of velocities are given, angle is not required. At the highest point the velocity will be zero (v = 0). Initial vertical velocity = u = 10 m/s. Acceleration a = - 9.8 m/s^2 (-ve because acceleration due to gravity is always downwards i.e. opposite of the +ve upwards displacement) Apply v = u + at to get t, the time to reach the highest point. Double that to get the time during which the ball is in air (T).

As the horizontal velocity remains constant throughout, determine horizontal displacement in time T (calculated above) using s = ut
 
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