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- Thread starter Padj01
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X=(Forward{X} movement - drag {Coefficient*normal force})

Y=(Upward{Y} movement - gravity + lift {coefficient*normal force})

Then, you can use a time-in-air formula.

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You are a far ways aways from the end of the problem, at this stage it is certainly not obvious which ""time-in-air formula" you are talking about.Then, you can use a time-in-air formula.

This is a tedious exercise in differential equations, solve these:

[tex] x'' + \frac{A}{m} x' = 0 [/tex]

[tex] y'' - \frac{L}{m} x' + g = 0 [/tex]

To get position x and y as functions of time. From here these, you can figure out how far things go (answer: find t @ y = 0 and solve for x(t).)

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