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badboyben03
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A stone is thrown horizontally at 14.0 m/s from a cliff 75.7 m high. How far from the base of the cliff does the stone strike the ground?
Projectile Stone Off Cliff question
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A stone is thrown horizontally at 14.0 m/s from a height of 75.7 m, and the discussion focuses on calculating how far it lands from the cliff's base. The method involves calculating the vertical velocity using the formula v = √(2gh) and determining the time taken to fall. Once the time is known, the horizontal distance can be calculated by multiplying the horizontal velocity by the time. There is a brief exchange regarding the meanings of variables g (acceleration due to gravity) and h (height), with some participants emphasizing the importance of self-study. The conversation highlights the need for understanding fundamental concepts in physics.
Neglect gravity other than that of water; neglect friction.
F1=ρgsh=1000*10*1*(1+4)=50000 N;
F1=ρgsh=1000*10*0.1*4=4000 N;
F3=50000-4000=46000 N?
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system
$$M(t) = M_{C} + m(t)$$
$$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$
$$P_i = Mv + u \, dm$$
$$P_f = (M + dm)(v + dv)$$
$$\Delta P = M \, dv + (v - u) \, dm$$
$$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$
$$F = u \frac{dm}{dt} = \rho A u^2$$
from conservation of momentum , the cannon recoils with the same force which it applies.
$$\quad \frac{dm}{dt}...
I was thinking using 2 purple mattress samples, and taping them together, I do want other ideas though, the main guidelines are;
Must have a volume LESS than 1600 cubic centimeters, and CAN'T exceed 25 cm in ANY direction.
Must be LESS than 1 kg.
NO parachutes.
NO glue or Tape can touch the egg.
MUST be able to take egg out in less than 1 minute.
Grade A large eggs will be used.
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