- #1
nix
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Prove that the period of a simple pendulum doing small oscillations is equal to:
2(py)x(square root of: l/g)
where py is 3.14..(obviously..lol)... l is length of the string of the pendulum and g is gravity
Also... the pendulum is basically just a ball on a string moving from side to side. and the equations we have been given to solve it is the fundamental eq. of an oscillation:
k = mw^2 = m x(2py^2/T) = m (2(py)f^2)
where f is the frequency, m is the mass, w is omega (the angle), and k is the spring constant and T is period
tricky..eh?
thanks for any help or suggestions..
2(py)x(square root of: l/g)
where py is 3.14..(obviously..lol)... l is length of the string of the pendulum and g is gravity
Also... the pendulum is basically just a ball on a string moving from side to side. and the equations we have been given to solve it is the fundamental eq. of an oscillation:
k = mw^2 = m x(2py^2/T) = m (2(py)f^2)
where f is the frequency, m is the mass, w is omega (the angle), and k is the spring constant and T is period
tricky..eh?
thanks for any help or suggestions..