rman144
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Prove the following is not true:
Let f : R^2->R^2 be a nonlinear function. For any vectors a,v in R^2;
f(a+v)-f(a)=[Df(a)]v
In terms of my attempt, I've been trying to find some combination of a and v that ensure this fails, but so far the best I've come up with is to start with:
[Df(a)]v=lim{h->0} (f(a+hv)-f(a))/h
And then trying to show that f(a+v)-f(a) is the same thing only as h->1; again, no luck. I really just need a hint or two as to which way to approach the proof.
Let f : R^2->R^2 be a nonlinear function. For any vectors a,v in R^2;
f(a+v)-f(a)=[Df(a)]v
In terms of my attempt, I've been trying to find some combination of a and v that ensure this fails, but so far the best I've come up with is to start with:
[Df(a)]v=lim{h->0} (f(a+hv)-f(a))/h
And then trying to show that f(a+v)-f(a) is the same thing only as h->1; again, no luck. I really just need a hint or two as to which way to approach the proof.