Proton, electron and coordinates

[21385]

Homework Statement

A proton sits at coordinates (x,y) = (0,0), and an electron at (d,h), where d>>h. At time t=0, a uniform electric field E of unknown magnitude but pointing in the positive y direction is turned on. Assuming that d is large enough that the proton-electron interaction is negligible, the y coordinates of the two particles will be equal (at equal time)

a) at about y=d/2000;
b)at an undetermined value since E is unknown;
c)at about y=d/43;
d)nowhere: they move in opposite directions

Homework Equations

E=F/q
F=ma

The Attempt at a Solution

The correct answer is a) but I don't know why. I have no idea how the answer connects d, a x-coordinate, with the final y-coordinate.

This is my attempt::

E=F/q
Since the E is the same and the q is the same, the 2 Forces must be the same
(mass of electron)(acceleration of electron)=(mass of proton)(acceleration of the proton)
(acceleration of electron)=1833(acceleration of proton)

S=(0.5)(acceleration of electron)t^2+(0.5)(acceleration of proton)t^2
of course, S=h-0 or S=h, and (acceleration of electron)=1833(acceleration of proton)
h=(0.5)(1833a(proton))t^2+(0.5)(a(proton))t^2
a(proton)=h/(917t^2)
I have no idea how to go from there...please help
Thanks a lot

 

[Doc Al]

The correct answer is a) but I don't know why. I have no idea how the answer connects d, a x-coordinate, with the final y-coordinate.

It makes no sense. I suspect a typo: The answers show "d" where they should show "h".

 

[21385]

Thanks, Doc Al
I got the problem, and it is y=h/1834

 

[Andy_ToK]

this is quite easy actually. Since the time elapsed is the same, the ratio between their displacements should be the inverse of that between their mass which is about 2000(very rough approximation ). So we get y=h/2001 so (a)