How to Calculate Acceleration of a Proton in a Magnetic Field

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To calculate the acceleration of a proton in a magnetic field, the key equation is F = q(v × B), where F is the force, q is the charge, v is the velocity, and B is the magnetic field strength. For the first problem, the proton's acceleration can be determined using this equation with the given magnetic field of 0.124 T and speed of 2.3 x 10^7 m/s. The second problem involves finding the speed of a proton moving eastward in Earth's magnetic field, which is 3.23 x 10^-5 T, while considering the acceleration due to gravity. Understanding the right-hand rule and the relationship between force, velocity, and magnetic field is essential for solving these problems. Utilizing the textbook for examples can provide further clarification on these concepts.
tmth
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I've got two homework questions I don't really understand. Coming to the end of the year so my teacher is rushing through things and forgetting to give us all the notes we need..
I think I need an equation to solve both of em, but I don't know what. Help/an explanation on how to do the problem is greatly appreciated. ^_^

#1) A proton moves at right angles to a magnetic field of .124 T with a speed of 2.3x10^7 m/s. Find the magnitude of the acceleration of the proton.

#2) A proton moves eastward in the plane of Earth's magnetic equator so that its distance from the ground remains constant. Assume the Earth's magnetic field at the equator is 3.23 x 10^-5 T. The acceleration of gravity is 9.8 m/s^2. What is the speed of the proton?
 
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tmth said:
I've got two homework questions I don't really understand. Coming to the end of the year so my teacher is rushing through things and forgetting to give us all the notes we need..
I think I need an equation to solve both of em, but I don't know what. Help/an explanation on how to do the problem is greatly appreciated. ^_^

#1) A proton moves at right angles to a magnetic field of .124 T with a speed of 2.3x10^7 m/s. Find the magnitude of the acceleration of the proton.

#2) A proton moves eastward in the plane of Earth's magnetic equator so that its distance from the ground remains constant. Assume the Earth's magnetic field at the equator is 3.23 x 10^-5 T. The acceleration of gravity is 9.8 m/s^2. What is the speed of the proton?

Have you covered {\vec F} = q {\vec v} \times {\vec B}? That is all that is needed (this equation means that the *direction* is given by the right hand rule and the *magnitude* of the force is the absolute value of the charge times v B sin (theta) where theta is the angle between the velocity vector and the magnetic field. This is all you need.
 
@_@ Haven't covered that.
 
tmth said:
@_@ Haven't covered that.
Then it is very strange that he expects you to do those problems if you haven't even seen the basic equation needed! I unfortunately don't have the time right now to explain it in details. You shoudl look at your textbook, I am sure they show examples!
 
Well, the problems come from an online problem set, and my teacher doesn't really look at the specific problems. And it *is* optional, but I want to do it to help my grade...
I got em right, with further help from the textbook. Thank you!
 
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