Proving grad(v_ . r_) = v_ with Spherical Polars | Math Gradient Help

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Homework Statement


hi, any help with proving that grad (v_ . r_) = v_ using spherical polars, where v_ is a uniform vector field would be great
it is trivial to prove using summation convention or cartesian coordinates but having to use spherical polars looks messy...

thanks

Homework Equations


as above/below...

The Attempt at a Solution


i know the identity: grad (a_.b_) = a x curl b + b x curl a + a . grad b + b . grad a
is it true that curl v_ and grad v_ are 0 since v_ is a uniform field? and grad r_ is the unit vector of r_? and curl r_ is 0? where i think r_ is the position vector...
 
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solved :)
thanks for the links, fzero
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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