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Homework Statement
Prove that \nabla\times(A\times B)= (B.\nabla)A-(A.\nabla)B-B(\nabla.A)+A(\nabla.B)
Homework Equations
bac-cab \nabla\times(A\times B)= (\nabla.B)A-(\nabla.A)B
The Attempt at a Solution
I know that B(\nabla.A)=(\nabla.A)B and A(\nabla.B)= (\nabla.B)A
So what about (B.\nabla)A-(A.\nabla)B=? Does it equal to zero? Or maybe bac cab is not related to this problem!