yifli
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Homework Statement
Prove that the sum B_r(\alpha)+B_s(\beta) is exactly the ball B_{r+s}(\alpha+\beta)
Homework Equations
open ball B_r(\alpha) of radius r about the center \alpha is \left \{\epsilon: |\alpha-\epsilon|<r\right\}
The Attempt at a Solution
I have difficulty of proving B_{r+s}(\alpha+\beta) \subset B_r(\alpha)+B_s(\beta)
any hints?
Thanks