Proving Velocity Averaging: <u> = 0, <u^2> = 1/3 <v^2> & <|u|> = 1/2 <v>

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The discussion focuses on proving three equations related to the velocity components of gas molecules. It emphasizes that the average velocity component <u> equals zero due to symmetry, while <u^2> is shown to equal 1/3 of the average squared speed <v^2>. Additionally, it establishes that the average magnitude of the velocity component <|u|> is half of the average speed <v>. The question also addresses the choice of the z-component for u, clarifying that any Cartesian component could be used without loss of generality. The integration approach is suggested to derive these relationships based on the given distribution of molecular velocities.
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Homework Statement



The molecules in a gas travel with different velocities. A particular molecule will have velocity v and speed v=|v| and will move at an angle X to some chosen fixed axis. The number of molecules in a gas with speeds between v and v + dv and moving at angles between X and X+dX to any chosen axis is given by

1/2 n f(v)dv sinX dX

Where n is the numberof molecules per unit volume and f(v) is some function of v only.

Show by integration that:

(a) <u> = 0
(b) <u^2> = 1/3 <v^2>
(c) <|u|> = 1/2 <v>

where u is anyone cartesian component of v i.e vx, vy or vz

The question says that we can take u as the z-component of v without loss of generality. Why is this? Could we equally well have taken it as the x or y-component. It then says express u in terms of v and X and average over v and X.


Homework Equations





The Attempt at a Solution



Not sure how I am meant to do this, so any help would be great - thanks!
 
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