# Pulley problem w/ friction

1. Sep 22, 2010

### hm8

1. The problem statement, all variables and given/known data
Three blocks are connected on the table as shown below. The table is rough and has a coefficient of kinetic friction of 0.420. The objects have masses of 4.00 kg, 1.00 kg and 2.00 kg, as shown, and the pulleys are frictionless.

Determine the acceleration of each object and their directions.

2. Relevant equations
F=ma
Ffriction=mu*normal force

3. The attempt at a solution
I made positive in the direction i think everything is moving...counterclockwise.

Fsystem = msystem*a
m1g-Ffriction-m2g = (m1+m2+m3)a
m_1g-(mu*m2g)-m2g = (m1+m2+m3)a

a = (m1g-(mu*m2g)-m2g)/(m1+m2+m3)

I plugged everything in and got 2.74 m/s^2.

I think it's okay that I ignored tension and made everything one system...although maybe I'm wrong about that.

It also could be that I got the answer right, and my teacher entered the wrong answer for our online homework thing so it's telling me I got it wrong...

Last edited: Sep 22, 2010
2. Sep 22, 2010

### collinsmark

Hello hm8,

Welcome to Physics Forums!
Check the above subscripts. Besides the indirect frictional part, the force of gravity on the middle block isn't contributing to the acceleration of the system. But what about block 3?

3. Sep 23, 2010

### hm8

That was a typo, sorry...using the 2kg block (block 3) gives me the answer 2.74 m/s^2.

My teacher also looked at my work today and said it looked okay, so I think it may just be a problem with how he programmed the answer into the online homework. Unless you see anything else wrong with it?

4. Sep 23, 2010

### collinsmark

Okay then, your
.....a = (m1g - μm2g - m3g)/(m1+m2+m3)
equation looks correct to me.

So the equation seems right to me, but something else does not (according to my calculations). See below.
Try plugging the numbers back into your equation. I get something different than 2.74 m/s2.

Last edited: Sep 23, 2010
5. Sep 23, 2010

### hm8

Ahh...for some reason I was forgetting to multiply by g for the friction of block to...I was just doing μ*m

The new answer (2.212 m/s^2) works! Thanks!