Pulley Question: Clarifying Fnetx Calculation

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In the discussion about the pulley system, the user seeks clarification on the net force calculations for the blocks involved. They understand that Fnetx equals tension (T) but are confused about why Fnety is expressed as Fw - T instead of T - Fw. The user initially thought that since tension points upward and weight (Fw) points downward, the equation should be T - Fw. However, it is explained that the convention is reversed to ensure that the acceleration remains positive for both blocks. This adjustment is necessary for consistent application of Newton's second law in the context of the system.
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I was wondering if someone could clarify this for me.
(this system of accelerating, the block on the right is heavier)
I know that Fnetx = T.

However, I'm a little confused about why Fnety should be Fw - T as opposed to T - Fw

When I was doing the free body diagram, for the y coord: T points up and Fw points down, so I was thinking since the standard coord system has up as +y and down as -y then Fnety = T - Fw, unfortunately it seems that it's necessary to reverse that.
 
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probably reversed so that acceleration comes out as a positive value for both blocks.
 

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