Pushing a box up a ramp a certain distance - work

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Homework Help Overview

The problem involves calculating the work done by a horizontal force acting on a crate moving up an inclined ramp. The crate has a weight and is subjected to gravitational forces, with the ramp inclined at 37 degrees. The original poster is seeking clarification on how to approach the calculation of work in this context.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the work done by considering the components of the pushing force and the weight of the crate. Some participants question whether the work done by other forces needs to be included in the calculation, particularly in relation to the overall work required to move the crate.

Discussion Status

Participants are exploring the distinction between calculating the work done by the pushing force alone versus the total work required to move the crate, which would involve considering additional forces. Clarifications have been offered regarding the focus of the problem.

Contextual Notes

The original poster expresses uncertainty about when to factor in the weight of the block in their calculations. There is an implication that the problem may have specific constraints or requirements regarding the forces to consider.

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Homework Statement



A horizontal 25 N pushing force acts on a 10 kg crate moving up a ramp. The ramp is inclined at 37 degrees above the horizontal.

How much work is done by this force in moving the crate a distance of 15m along the ramp?

Homework Equations



W = Fd

The Attempt at a Solution



This was on a previous test i took and i got it wrong and now looking over it again i cannot seem to figure it out.

I thought i could take the component of the pushing force parallel to the ramp and subtract the component of the weight of the block that is parallel to the ramp then just multiply that by the distance but that didnt work out to well.

here is was i did

The component of the pushing force parallel to the ramp is

25cos(37) = 19.96

the component of the weight parallel to the ramp (and opposite in direction of the component of the pushing force parallel to the ramp) is

mgsin(37)

10(9.8m/s^2)sin(37) = 58.9

so subtract those two

19.9 - 58.9 = - 39N

so W = 39N(15m)

W = 585 J

the correct answer is 300 J

Any help would be great.

Thank you :)
 
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You are calculating the work done by the pushing force and gravity (and you left out the minus sign). But the problem asks for the work done by the pushing force only.
 
oh so since its just the work done by the pushing force, i don't even have to factor in the other forces. Got it.

If it would have asked how much work does it take to move the block 15 m then would that mean i would have to factor in the other forces like i did in my first post?

I just feel like i don't know when i would have to consider the forces of the weight of the block being pushed.
 
Last edited:
If this problem would have asked for the total work required to push the block up the ramp 15 m then would i have had to consider in the force of gravity like i did in my first post?
 
mybrohshi5 said:
If this problem would have asked for the total work required to push the block up the ramp 15 m then would i have had to consider in the force of gravity like i did in my first post?
You'd have to consider the work done by all forces to calculate the total work done on the block. In your example, the block would not move up the ramp if there were no other forces acting besides the pushing force and the block's weight, so there has to be anothner force acting (not given) to move it up.
 

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