Q: Finding Resultant Forces with Unknown Magnitude and Angle

AI Thread Summary
The discussion revolves around calculating the resultant forces from two cables supporting a chin brace for an injured jaw. The cables are positioned at 65 degrees above the horizontal, producing equal forces with a vertical resultant of 2.30N. Participants express confusion about estimating angles and calculating the magnitudes of the left and right forces, with some suggesting the use of free body diagrams and trigonometric equations. There is a debate about the need for additional information, such as the mass of the head, to accurately calculate the forces. The conversation emphasizes the importance of understanding the balance of forces in both the vertical and horizontal directions to solve the problem effectively.
rpgnick85
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Homework Statement



Q: Make a scale drawing showing both the forces produced by the cables and the resultant force. Estimate the angle carefully or measure it with a protractor.

Supplement:
A person with an injured jaw has a brace below his chin. The brace is held in place by two cables directed at 65 above the horizontal. (See the figure.) The cables produce forces of equal magnitude having a vertical resultant of 2.30 upward.


I don't have a protractor and would like to go about the estimate mathematically. I am having trouble finding the right and left lengths. I am guessing the resultant vector is length 2.30N and 90 degrees? If someone could walk me through it for understanding that would be great.
 

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or if someone could point me in the right direction i have no idea where to begin
 
rpgnick85 said:

Homework Statement



Q: Make a scale drawing showing both the forces produced by the cables and the resultant force. Estimate the angle carefully or measure it with a protractor.

Supplement:
A person with an injured jaw has a brace below his chin. The brace is held in place by two cables directed at 65 above the horizontal. (See the figure.) The cables produce forces of equal magnitude having a vertical resultant of 2.30 upward.


I don't have a protractor and would like to go about the estimate mathematically. I am having trouble finding the right and left lengths. I am guessing the resultant vector is length 2.30N and 90 degrees? If someone could walk me through it for understanding that would be great.

Why do you need to estimate some angles if the angles are labeled already for you? I'm missing something there.

And just draw the components of the two angled forces. The two vertical components need to sum to the total weight of the head, right?
 
I need to find the magnitude of the left pulling force and right pulling force. The upward resultant is 2.30N and 90 degrees? The angle of the left is 115 degrees and angle of the right is 65 degrees not sure N force though.
 
rpgnick85 said:
I need to find the magnitude of the left pulling force and right pulling force. The upward resultant is 2.30N and 90 degrees? The angle of the left is 115 degrees and angle of the right is 65 degrees not sure N force though.

So just draw a free body diagram (FBD) for the bottom of the chin brace, showing the resultant force, and the components of the two strings. The vertical components of the string forces must sum to what? And the horizontal components must sum to what?

Use the angles and basic trig to calculate the magnitudes of the vertical and horizontal string force components. Please show us your work...
 
I did the vertical force at 90 degrees by 2.3N. The left diagonal force I did 115 degrees and the right diagonal force I did 65 degrees. I am having trouble finding the magnitude of the left and right forces.

I tried (2.3)^2 = sqrt(x^2 + x^2) I did x^2 twice because of two equal forces pulling in opposite directions to find each magnitude. I also tried 4.6 for each magnitude. I feel like I don't have enough info or I am missing something.

Check my image.
 

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rpgnick85 said:
I did the vertical force at 90 degrees by 2.3N. The left diagonal force I did 115 degrees and the right diagonal force I did 65 degrees. I am having trouble finding the magnitude of the left and right forces.

I tried (2.3)^2 = sqrt(x^2 + x^2) I did x^2 twice because of two equal forces pulling in opposite directions to find each magnitude. I also tried 4.6 for each magnitude. I feel like I don't have enough info or I am missing something.

Check my image.

The diagram looks reasonable, except you need to also show the force down due to gravity. What is the magnitude of the downforce due to gravity?

Write an equation for the sum of the horizontal forces in the horizontal direction. What is the sum equal to?

Write an equation for the sum of the vertical forces in the vertical direction. What is the sum equal to?
 
Good place to start, I am guessing 1N is the downforce due to gravity and that will help me find the horizontal and vertical forceS?
 
rpgnick85 said:
Good place to start, I am guessing 1N is the downforce due to gravity and that will help me find the horizontal and vertical forceS?

First it is important to understand what the sum of the forces in each of the two dimensions must equal.

Since F=ma, what do the vertical forces need to all add up to? And the horizontal forces?
 
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We don't have the mass of the head. I set Yleft and Yright to 2.30 and solved for Xleft and Xright in which I got 1.075 and magnitude of 2.54 for each direction (after left = sqrt(x^2 + y^2). That answer was wrong. But the resultant magnitude is 2.30N and the resultant angle is 90 degrees. Are we assuming m = 1 and having F = 9.8? or are we setting 2.30N = m * 9.8? I can find resultant forces when I have the magnitude and angles of each direction already but I am having difficulty without the magnitude.
 
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