- #1
cscott
- 782
- 1
This was on a test but I couldn't quite solve for x:
[tex]5^2^x + 4(5)^x = -3[/tex]
let [itex]5^x = y[/itex]
[tex]y^2 + 4y + 3 = 0[/tex]
[tex](y + 1)(y + 3) = 0[/tex]
So I end up with [itex]5^x = -1[/itex] or [itex]5^x = -3[/itex], but I don't think that makes sense... what am I doing wrong? It must be something dumb I'm doing :shy:
[tex]5^2^x + 4(5)^x = -3[/tex]
let [itex]5^x = y[/itex]
[tex]y^2 + 4y + 3 = 0[/tex]
[tex](y + 1)(y + 3) = 0[/tex]
So I end up with [itex]5^x = -1[/itex] or [itex]5^x = -3[/itex], but I don't think that makes sense... what am I doing wrong? It must be something dumb I'm doing :shy:
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