So a quarter circle has a total charge of 25μC and has a 1m radius.
I need to find the resultant electric field at point P.
The Y components will cancel here due to symmetry so we are left only caring about the x components.
dE= (kdq)/(r^2) rˆ
The Attempt at a Solution
I don't have a value for lambda, so...
Q= ∫λdl from 0 to (pi * r / 2) because 1/4 of 2*pi*r
25uC = λ*pi*1/4
k/r^2 * q = E
(9*10^9)/(1^2) * 31.83 = 2.86*10^11
The answer is really E = 2.03*10^5 N/C
I know I'm going wrong at the integration but I don't know how to solve it.