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## Homework Statement

So a quarter circle has a total charge of 25μC and has a 1m radius.

I need to find the resultant electric field at point P.

## Homework Equations

The Y components will cancel here due to symmetry so we are left only caring about the x components.

**dE= (kdq)/(r^2) rˆ**

**dq= λdl**

## The Attempt at a Solution

I don't have a value for lambda, so...

dq= λdl

Q= ∫

**λdl from 0 to (pi * r / 2) because 1/4 of 2*pi*r**

Q=

**λ∫dl**

25uC =

**λ*pi*1/4**

**λ= 31.83uC/m**

k/r^2 * q = E

(9*10^9)/(1^2) * 31.83 = 2.86*10^11

The answer is really E = 2.03*10^5 N/C

I know I'm going wrong at the integration but I don't know how to solve it.k/r^2 * q = E

(9*10^9)/(1^2) * 31.83 = 2.86*10^11

The answer is really E = 2.03*10^5 N/C

I know I'm going wrong at the integration but I don't know how to solve it.

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