Question about omega (angular velocity)

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In an AC circuit with a capacitor, the angular velocity ω is determined by the input frequency, such as 105 rad/s in the given example, rather than being equal to 1/RC. The time constant RC is relevant for analyzing the circuit's behavior, particularly in relation to cutoff frequency (ωc), which is a characteristic of the circuit itself. The impedance of a capacitor remains Zc(jω) = 1/jωC, regardless of whether an op-amp is present in the circuit. Confusion often arises between ω, which pertains to the input frequency, and ωc, which indicates the cutoff frequency where the circuit's response changes. Understanding these distinctions is crucial for analyzing filter behavior and circuit performance.
ThomasHW
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For a capacitor in an AC circuit, does \omega = \frac{1}{RC} always?

I have voltages such as Vg = 2cos(105t) V. When finding the capacitance using the formula C = \frac{1}{jwc} would I use \omega = 105 or would I use \omega = \frac{1}{RC}?
 
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ω=105 rad/s

RC is the time constant of an RC circuit.
 
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Does it change anything if the circuit involves an op-amp?
 
When people say "RC" circuit they usually mean that there is no op-amp. Some op-amp circuits with resistor and capacitor still have the time constance RC.

The impedance of a capacitor is still 1/jωC in either case.
 
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If I had a voltage Vg = 2cos(105t) V going into the op-amp, would I still use 105 rad/s as my angular velocity, or \frac{1}{RC}?
 
Your question doesn't make a lot of sense to me, but ω is 105.

I said something wrong previous, the time constant is RC.

Sometimes when you are working with a system, the equation ωc = 1/RC would come up. This ωc is the cutoff frequency. Are you getting ω and ωc mixed up? ωc is a property of the circuit. ω is a parameter of the input.
 
Probably. I've had to use RC for a high-pass and low-pass filter, but I guess that's because of they have a cut-off frequency.

I guess I'm confused as to when RC and when to use 1/jwc.
 
ωc is a property of a circuit. Suppose you were to sketch the Bode plot of an RC low pass filter. For the magnitude plot, if you just draw the linear approximation, you get two lines segments that meet at a frequency. The frequency that they meet is ωc. Because ωc is where the curve bends, ωc is also called the corner frequency. The significant of ωc is that it is where the input sinusoid gets 'cutoff'.

ω is the frequency of the input. In this low pass example, if ω > ωc, then the input is cutoff.Zc(jω) = 1/jωC is the impedance of a capacitor. It is the ratio of the voltage and current across a capacitor. It is the ratio Vc(jω)/Ic(jω). It is analogous to resistance, where R = V/I.
 

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