How to Determine Velocity and Maximum Compression of a Pendulum-Spring System

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To determine the velocity of a pendulum ball at the bottom of the swing, the formula v = sqrt(2gh) is used, yielding a velocity of 1.00 m/s based on a height calculation. For maximum compression of the spring, energy conservation principles apply, leading to the equation 1/2 mv^2 = 1/2 ke^2, which simplifies to e = sqrt(mv^2 / k). Substituting the values results in a maximum compression of approximately 0.036 m. Both calculations were confirmed as correct by participants in the discussion. The methodology effectively combines gravitational potential energy and spring potential energy principles.
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Homework Statement


Hi, I have a question about pendelum which I don't know how to solve

A 1.0 kg ball swings from a pendulum and bounces into a spring with a spring constant of 750 N/m.

Here is the diagram:
Untitled.png


1. How do i determine velocity of the ball at the bottom of the swing?
2. How do i determine the maximum compression of the spring?

Homework Equations


The Attempt at a Solution


Attempt for number 1

h = 1.5 m - (1.5 m cos 15)
h = 0.05111126 m

Eg = Ek
mgh = 1/2 mv^2
gh = 1/2 mv^2
2gh = v^2
sqrt(2gh) = v

v = 1.00 m/s
Is that right?

2. I don't know how to do 2.

Thanks
 
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silentcoder said:
sqrt(2gh) = v

v = 1.00 m/s
That's a remarkable leap. What do you think h equals?
For part 2, use energy again. How fast will the ball be moving when the spring is at maximum compression?
 
haruspex said:
That's a remarkable leap. What do you think h equals?
For part 2, use energy again. How fast will the ball be moving when the spring is at maximum
compression?

For number 1:
sqrt(2gh) = v
sqrt(2(9.81)(1.5 - 1.5 cos 15))
v = 1.0 m/s

For number 2:
1/2 mv^2 = 1/2 ke^2
mv^2 = ke^2
e^2 = mv^2 / k
e^2 = (1.0 kg)(1 m/s)^2 / 750 N/m
e^2 = 1/750
e = sqrt(1/750)
e = 0.036 m

is this right?
 
Looks good.
 
haruspex said:
Looks good.

For both of them?

If yes, Thank You for verification!
 
Yes, both.
 
haruspex said:
Yes, both.

Appreciate your help!
 
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