Question on Fluid Pressure in Pipes

AI Thread Summary
In fluid mechanics, pressure drops in pipes with uniform diameter occur due to friction, which is influenced by the pipe's relative roughness. Unlike the Bernoulli equation, which assumes constant pressure, the presence of friction results in a gradual pressure decrease along the pipe length. This frictional loss is a key factor in understanding fluid flow in real-world applications. The discussion emphasizes the importance of considering friction factors when analyzing fluid behavior in pipes. Understanding these concepts is essential for solving fluid mechanics problems effectively.
!Live_4Ever!
Messages
45
Reaction score
0
Hi, I was doing my fluid mechanics howework, and there was a question that I couln't quite answer.

Assuming that the integral of the axial momentum remains constant along the pipe cross section, the pressure drops uniformly along the pipe length. (Contrary to the Bernulli equation where the pressure is supposed to stay constant)

I was wondering if anyone had a non-mathematical way of explaing why a pressure drop exists in a pipe with uniform diameter..

Thanks, as always.
 
Physics news on Phys.org
In all pipes there is a relative roughness which is associated with a friction factor. This friction can cause pressure drops.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top