Engineering Questions regarding AC circuits

AI Thread Summary
The discussion revolves around understanding complex admittance in AC circuits, specifically addressing the sign of susceptance B in relation to inductive reactance X_L. The confusion arises from the negative sign in the expression for B, which some participants suggest may stem from the nature of complex numbers and their application in physical laws. Additionally, the thread explores the calculation of complex power S, emphasizing the necessity of using the complex conjugate of current I to obtain accurate results. Participants also seek clarification on applying Kirchhoff's Second Law in circuits with mutual inductance, indicating a need for a deeper understanding of the underlying principles. Overall, the conversation highlights the complexities of AC circuit analysis and the mathematical interpretations involved.
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Suppose that we have a simple system like one illustrated in attachment.

If we need to find complex admittance of that system,we can write:

<br /> \underline{Y}=G+jB=\frac{1}{\underline{Z}}=\frac{1 }{R+jX_L}\cdot\frac{R-jX_L}{R-jX_L}=\frac{R-jX_L}{R^2+X_L^2}=\frac{R}{R^2+X_L^2}+j\frac{-X_L}{R^2+X_L^2}<br />

from where we can see that it is B=\frac{-X_L}{R^2+X_L^2},althought it is B=\frac{X_L}{R^2+X_L^2}.

Why is this "-" just neglected,what is physical explanation of that?

Or it is just hardcore mathematical laws against imperfect physical reality?

Also,is it because complex numbers are just,let`s say it like this,"artificial" extension of real numbers set?

Probably the explanation is that while one physical parameter is rising(susceptance B),the other is lowering(inductive reactance X_L) and vice-versa,like it is in Faraday`s law of induction:

e=-\frac{d\phi}{dt}

the magnetic field which is produced by induced current(which is in turn produced by induced electromotive force e) is in oposition with the change of outer flux \phi(sorry if my technical english sounds a bit clumsy).

But what if there is capacitor instead of inductor?
In that case there is no confusion like this.

There is also a "-" when active and reactive power for system like one illustrated in attachment is calculated.
 

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The second question is regarding complex power \underline{S}:

why expression \underline{S}=\underline{U}\;\underline{I} does not give the correct result,instead of that it is used \underline{S}=\underline{U}\;\underline{I}^* where \underline{I}^* is complex-conjugate of \underline{I}?
 
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I hope I will have more luck with this one:

In given circuit:

http://img90.imageshack.us/img90/9085/clipboard05xw4.gif

where is:

R_1=10\;\Omega, R_3=2,5\;\Omega, R_2=X_C=X_L=5\;\Omega and \underline{E}=50e^{j\frac{\pi}{2}}\;V,

find the value of current source \underline{I}_S.

Voltage drop on R_3 is \underline{U}=100\;V.


First I calculate current trough R_3: \underline{I}_{R_3}=\frac{\underline{U}}{R_3}=40\;A.


Further,by using Superposition theorem and removing branch containing \underline{I}_s I find that \underline{E} produces current of j20.When I substract that value from \underline{I}_{R_3} I get \underline{I}_S=(40-j20)\;V.

However,correct result is \underline{I}_S=(-10+j20)\;V.

What I do wrong?
 
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Problem 4:

Could someone explain to me how to write equations using 2nd Kirchoff`s Law along the closed loop in circuit where we have mutual inductance between two inductors?

I can`t comprehend this correctly at all.

Here is example circuit:

http://img125.imageshack.us/img125/4779/clipboard033mw7.jpg

The closest I was was equation with difference in one + instedad of -.

I need explanation here,not just equations,I already have them.
 
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